(m+m^-1+2)⼀(m^-1⼀2+m^1⼀2)*(m^-2⼀3-m3⼀2)⼀(m+m^-1+1)

2025-01-19 08:18:25
推荐回答(1个)
回答1:

(m+m^-1+2)/(m^-1/2+m^1/2)*(m^-3/2-m^3/2)/(m+m^-1+1)
=(m^1/2+m^-1/2)^2/(m^-1/2+m^1/2)*(m^-1/2-m^1/2)*(m+m^-1+1)/(m+m^-1+1)
=(m^1/2+m^-1/2)*(m^-1/2-m^1/2)
=m^-1-m
=1/m-m