求F(s)=(s+2)(s+3)⼀(s+1)的拉氏反变换

求F(s)=(s+2)(s+3)/(s+1)的拉氏反变换求全过程
2025-01-19 11:03:42
推荐回答(1个)
回答1:

s3+21s2+120s+100 =s3+s2+20s2+120s+100 =s2(s+1)+20(s2+6s+5) =s2(s+1)+20(s+1)(s+5) =(s+1)(s2+20s+100) =(s+1)(s+10)2