x눀-x-12=0 用因式分解法解

2025-01-18 20:30:22
推荐回答(1个)
回答1:

x²-x-12=0
x²-4x+3x-12=0
x(x-4)+3(x-4)=0
(x-4)(x+3)=0
x=4,x=-3