求1⼀(2+sin2x)的不定积分

谢谢了
2024-11-08 14:17:49
推荐回答(1个)
回答1:

=∫1/(2+2cos²(x-π/4)-1)dx
=∫sec²(x-π/4)/(sec²(x-π/4)+2)dx
=∫1/(tan²(x-π/4)+3)dtan(x-π/4)
=(1/√3)arctan(tan(x-π/4)/√3)+C