定积分 求三点、两线段、和曲线围成的面积,曲线是y=-x^2,左上为原点

2025-01-21 15:46:14
推荐回答(1个)
回答1:

当y = - 2时
- x² = - 2
x = ± √2
x = √2

= ∫(0→√2) (- x²) dx
= - x³/3 |(0→√2)
= - 2^(3/2)/3 + 0
= - (2√2)/3
面积 = |∫(0→√2) (- x²) dx| = (2√2)/3