y'=ln(x-2)+x/(x-2)=ln(x-2)+2/(x-2)+1y''=1/(x-2)-2/(x-2)^2望采纳
y=xln(x-2)y'=ln(x-2) + x/(x-2) =ln(x-2) + 1 + 1/(x-2)y''=1/(x-2) -1/(x-2)^2
y'=ln(x-2)+x/(x-2)y''=1/(x-2)+1/(x-2)-x/(x-2)²=(x-4)/(x-2)²
