y''= [(1-x^2)/(x^2+1)^2]'= {(1-x^2)'(x^2+1)^2-(1-x^2)[(x^2+1)^2]'}/(x^2+1)^4= {(-2x(x^2+1)^2-(1-x^2)[2(x^2+1)]*2x}/(x^2+1)^4=[-2x(x^2+1)-4x(1-x^2)]/(x^2+1)^3=2x(x^2-3)/(x^2+1)^3解答步骤如上,你看那一步的系数错了。
(u/v)′=(u′v-uv′)/v²