麻烦大神帮忙y=2ln(x+1)的求导为什么我求倒出来是x分子2怎么求导,过程

2025-01-21 04:56:57
推荐回答(1个)
回答1:

y=2ln(x+1)
y'
=2d/dx ln(x+1)
=2. [d/d(x+1) ln(x+1) ]. d/dx (x+1)
= 2. [1/(x+1) ]. (1)
=2/(x+1)