推荐回答(1个)
初级线圈匝数=输入电压*次级线圈匝数/空载电压,铜线一平方毫米为5A.,根据 功率=电流×电压可算出电流,初级电流=5KW/输入电压;电焊机空载电压一般为70伏,工作电压一般为30-40伏,靠电抗绕组调节,次级电流=5000/35=143,143/5=28.6,可据此选择合适的线径。
绝缘布烧焦是不可用的.再照原电孤电焊机线圈的扁平线买些绕好,如果扁平线在2*4mm^2以下,用手掏绕就可以了.只是头、尾接头要处理好。
变压器是闭合铁心上绕有初级和次级线圈的装置,初级线圈通交流电,交流电就在铁心内产生交变的磁场,这个磁场在次级线圈感应出感生电动势,就将电流由初级传送到了次级.由于是磁场变化(由初级变化电流产生),在次级产生电流.所以直流电就不能通过变压器传送.由于初、次级线圈圈数不同,就可以产生电压的变化,这是简单的原理 一.变压器的工作原理 变压器---利用电磁感应原理,从一个电路向另一个电路传递电能或传输信号的一种电器是电能传递或作为信号传输的重要元件
变压器 ---- 静止的电磁装置 变压器可将一种电压的交流电能变换为同频率的另一种电压的交流电能 电压器的主要部件是一个铁心和套在铁心上的两个绕组。 变压器原理图(图3.1.2) 与电源相连的线圈,接收交流电能,称为一次绕组 与负载相连的线圈,送出交流电能,称为二次绕组 设 一次绕组的 二次绕组的 电压相量 U1 电压相量 U2 电流相量 I1 电流相量 I2 电动势相量 E1 电动势相量 E2 匝数 N1 匝数 N2 同时交链一次,二次绕组的磁通量的相量为 φm ,该磁通量称为主磁通 请注意 图3.1.2 各物理量的参考方向确定。
理想变压器 不计一次、二次绕组的电阻和铁耗, 其间耦合系数 K=1 的变压器称之为理想变压器 描述理想变压器的电动势平衡方程式为 e1(t) = -N1 d φ/dt e2(t) = -N2 d φ/dt 若一次、二次绕组的电压、电动势的瞬时值均按正弦规律变化, 则有 不计铁心损失,根据能量守恒原理可得 由此得出一次、二次绕组电压和电流有效值的关系 令 K=N1/N2,称为匝比(亦称电压比)
参考资料
李强.机电技术.科学出版社:北京大学,1996
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