y✀-xy✀=a(y^2 +y) 微积分的通解或特解

2025-01-21 06:00:05
推荐回答(2个)
回答1:

简单分析一下,答案如图所示

回答2:

y'(1-x)=a(y^2+y)
dy/(y^2+y) =adx/(1-x)
dy(1/y-1/(y+1) )=adx(1-x)
lny - ln(y+1) =-aln(1-x)+C