数列{an}满足a1=1,a2=1,an+2=(1+sin2nπ2)an+4cos2nπ2,则a9,a10的大小关系为(  )A.a9>a10B.

2025-01-20 10:49:55
推荐回答(1个)
回答1:

当n为偶数时,an+2=(1+0)an+4×1=an+4,偶数项构成以4为公差的等差数列.
a10=a2+(5-1)×4=1+16=17.
当n为奇数时,an+2=(1+1)an+4×0=2an,奇数项构成以2为公比的等比数列.
a9=a1?24=1×16=16,
所以a9<a10
故选C.