当n为偶数时,an+2=(1+0)an+4×1=an+4,偶数项构成以4为公差的等差数列.a10=a2+(5-1)×4=1+16=17.当n为奇数时,an+2=(1+1)an+4×0=2an,奇数项构成以2为公比的等比数列.a9=a1?24=1×16=16,所以a9<a10故选C.