y=√2/2(cos3x-sin3x)=-sin(3x-π/4)，y=sin(-3x)=-sin(3x)
所以y=sin(-3x)向右移动π/4即得y=√2/2(cos3x-sin3x)
(x)=√3cos(2x/5)+sin(2x/5)
=2[√3cos(2x/5)/2+sin(2x/5)/2]
=2[sin(π/3)cos(2x/5)+cos(π/3)sin(2x/5)]
=2sin(2x/5+π/3)
f(x)的周期为2π/(2/5)=5π
2sin(2x/5+π/3)的对称轴之间的距离即为f(x)的半周期
f(x)两条对称轴之间的距离是5π/2
或者这样解
当2x/5+π/3=π/2时,x=5π/12
当2x/5+π/3=-π/2时,x=-25π/12
5π/12-(-25π/12)=5π/2
f(x)两条对称轴之间的距离是5π/2
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