解下列方程:(1)2x+13?10x+16=1; (2)0.1x?0.20.02?x+10.5=3.

解下列方程:(1)2x+13?10x+16=1; (2)0.1x?0.20.02?x+10.5=3.
2025-03-26 11:38:05
推荐回答(1个)
回答1:

(1)去分母得,2(2x+1)-(10x+1)=6,
去括号得,4x+2-10x-1=6,
移项得,4x-10x=6+1-2,
合并同类项得,-6x=5,
x的系数化为1得,x=-
5
6


(2)把原式的分母化为整数得,
10x?20
2
-
10x+10
5
=3,
去分母得,5(10x-20)-2(10x+10)=30,
去括号得,50x-100-20x-20=30,
移项得,50x-20x=30+100+20,
合并同类项得,30x=150,
x的系数化为1得,x=5.