解：∫[-1,0][(3x^4+3x^2+1)/(1+x^2)]dx=∫[-1,0] 3x^2dx +∫[-1,0] 1/(1+x^2)]dx=x^3 | [-1,0] + acrtanx | [-1,0]=0^3 - (-1)^3 +0-（-π/4）=1+π/4
