复合函数的求导问题

2025-01-20 15:54:32
推荐回答(2个)
回答1:

复合函数的求导公式

回答2:

y= sin(x^2)

y' 

= cos(x^2) . d/dx (x^2)

= 2x.cos(x^2)

y= (sinx)^2

y'

=2sinx . d/dx(sinx)

=2sinx.cosx