用3、4、6、13进行四则运算，规定“加减乘除”各用一次，可以添括号并使结果等于24，怎样列算式呢？

1: (3 + 13) ÷ 4 × 6
2: ((3 + 13) ÷ 4) × 6
3: (3 + 13) ÷ (4 ÷ 6)
4: (3 + 13) × 6 ÷ 4
5: ((3 + 13) × 6) ÷ 4
6: (3 + 13) × (6 ÷ 4)
7: (6 × (3 + 13)) ÷ 4
8: 6 × (3 + 13) ÷ 4
9: 6 × ((3 + 13) ÷ 4)
10: 6 ÷ 4 ×(3 + 13)
11: (6 ÷ 4) × (3 + 13)
12: 6 ÷ (4 ÷ (3 + 13))
13: 6 ÷ 4 ×(13 + 3)
14: (6 ÷ 4) × (13 + 3)
15: 6 ÷ (4 ÷ (13 + 3))
16: (6 × (13 + 3)) ÷ 4
17: 6 × (13 + 3) ÷ 4
18: 6 × ((13 + 3) ÷ 4)
19: 6 ÷ (13 ÷ 4 - 3)
20: 6 ÷ ((13 ÷ 4) - 3)
21: (13 + 3) ÷ 4 × 6
22: ((13 + 3) ÷ 4) × 6
23: (13 + 3) ÷ (4 ÷ 6)
24: (13 + 3) × 6 ÷ 4
25: ((13 + 3) × 6) ÷ 4
26: (13 + 3) × (6 ÷ 4)
就是搞不清楚，3个数怎么用4个符号

题有问题，4个数，只能用3个运算符号，用不了4个

十三加三除四乘六

（3+13）÷4×6