c语言中关于sscanf函数的运用及%n的用法

2025-02-19 13:38:29
推荐回答(4个)
回答1:

代码如下:

#include

#include

int main (){

    char s[200];

    int n,wei;

    memset(s,0,sizeof(s));

    while(gets(s)){

        int cnt=0,sum=0,num;

        char *p=s;

        while(sscanf(p,"%d%n",&n,&wei)==1){

            sum+=n;cnt++;wei++;    

            if(p) p+=wei;

        }

        printf("%d %d\n",cnt,sum);

        memset(s,0,sizeof(s));

    }

    return 0;

}

扩展资料

scanf()函数是通用终端格式化输入函数,它从标准输入设备(键盘) 读取输入的信息。可以读入任何固有类型的数据并自动把数值变换成适当的机内格式。

scanf()函数返回成功赋值的数据项数,出错时则返回EOF。

其控制串由三类字符构成:

1、格式化说明符;

2、空白符;

3、非空白符;

用空白符结尾时,scanf会跳过空白符去读下一个字符,所以必须再输入一个数。这里的空白符包括空格,制表符,换行符,回车符和换页符。所以如果用scanf("%d ",&a)也会出现同样的问题。

回答2:

1).sscanf函数的运用:
函数原型:
int sscanf( const char *, const char *, ...);
int sscanf(const char *buffer,const char *format,[argument ]...);
buffer存储的数据
format格式控制字符串
argument 选择性设定字符串
sscanf会从buffer里读进数据,依照format的格式将数据写入到argument里。

sscanf与scanf类似,都是用于输入的,只是后者以键盘(stdin)为输入源,前者以固定字符串为输入源。
第二个参数可以是一个或多个 {%[*] [width] [{h | I | I64 | L}]type | ' ' | '\t' | '\n' | 非%符号}
注:
1、 * 亦可用于格式中, (即 %*d 和 %*s) 加了星号 (*) 表示跳过此数据不读入. (也就是不把此数据读入参数中)
2、{a|b|c}表示a,b,c中选一,[d],表示可以有d也可以没有d。
3、width表示读取宽度。
4、{h | l | I64 | L}:参数的size,通常h表示单字节size,I表示2字节 size,L表示4字节size(double例外),l64表示8字节size。
5、type :这就很多了,就是%s,%d之类。
6、特别的:%*[width] [{h | l | I64 | L}]type 表示满足该条件的被过滤掉,不会向目标参数中写入值
失败返回0 ,否则返回格式化的参数个数

2)%n的用法
%n说明符输出有效字符数量,%n在scanf和printf中都可使用。与%n相对应的形参是一个int类型的指针,%n不影响scanf和printf的返回值。例如:
scanf("%d %d%n", &i, &j, &k);
如果输入434 6434,则k等于8,而scanf的返回值仍然为2。又如:
scanf("%c%n", &ch, &k);
输入“sbcdefdg”后,k等于1,而不是8,因为%c只取一个字符,%n输出的是有效字符数量。
%n用在printf函数里,表示输出的字符数量,例如:
printf("i=%d, j=%d\n%n", i, j, &k);
在i=343、j=123的情况下,k=12,同时%n不影响printf的返回值,其返回值仍然为12,而不是14。

回答3:

%n 可以将所输出字符串的长度值赋绐一个变量, 见下例:
int slen;
printf("hello world%n", &slen);
执行后变量被赋值为11。

sscanf和scanf类似,只是从字符串输入而已
sscanf(p,"%s%n",a,&t)就是将字符串p输入到a中,长度赋值到t

回答4:

楼上谢谢你的回答 很好

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