空心方阵求总人数的公式如何理解,(最外层每边人数—层数)*层数*4,请教了,谢谢
推荐回答(2个)
1、方阵外一层总人数比内一层的总人数多8
2、每边人数与该层人数关系是:最外层总人数=(边人数-1)×4
3、方阵总人数=最外层每边人数的平方
4、空心方阵的总人(或物)数=(最外层每边人(或物)数-空心方阵的层数)×空心方阵的层数×4
5、去掉一行、一列的总人数=去掉的每边人数*2-1
例:某校的学生刚好排成一个方阵,最外层的人数是96人,问这个学校共有学生?
析:最外层每边的人数是96/4+1=25,刚共有学生25*25=625
例:五年级学生分成两队参加学校广播操比赛,他们排成甲乙两个方阵,其中甲方阵每边的人数等于8,如果两队合并,可以另排成一个空心的丙方阵,丙方阵每边的人数比乙方阵每边的人数多4人,甲方阵的人数正好填满丙方阵的空心。五年级参加广播操比赛的一共有多少人?
析:设乙最外边每人数为Y,则丙为Y+4.
8*8+Y*Y+8*8=(Y+4)(Y+4)
求出Y=14,则共有人数:14*14+8*8=260
例:明明用围棋子摆成一个三层空心方阵,如果最外层每边有围棋子15个,明明摆这个方阵最里层一周共有多少棋子?摆这个三层空心方阵共用了多少个棋子?
析:最外层有(15-1)*4=56个。则里二层为56-8*2=40
应用公式,用棋子(15-3)*3*4=144
空心方阵求总人数,画出示意图,将总人数分成四个等腰梯形
每一个等腰梯形,下底=最外层每边人数-1,高=层数,
每向内一层,人数少2,上底=最外层每边人数-1-2*(层数-1)=最外层每边人数-2*层数+1,
面积=1/2*[上底+下底]*高
=1/2*[最外层每边人数-2*层数+1+最外层每边人数-1]*层数
=1/2*[2*最外层每边人数-2*层数]*层数
=(最外层每边人数-层数)*层数
总人数=(最外层每边人数-层数)*层数*4
举例:
某空心方阵,最外层每边人数100,层数5
最内层每边人数92
总人数=1/2*(99+91)*5*4=1900 人
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