如图,AD是△ABC的边BC上的中线,点E在AD上,AE=2DE,若△ABE的面积是4,那么△ABC的面积是(  ) A

2025-01-20 20:59:29
推荐回答(1个)
回答1:

∵AE=2DE,
∴AD=3DE,
∴S △ABE :S △ABD =AE:AD=2DE:3DE=2:3.
又∵△ABE的面积是4,
∴S △ABD =6.
∵AD是△ABC的边BC上的中线,
∴BD=CD,
∴S △ABD :S △ADC =BD:CD=1:1,
∴S △ADC =S △ABD =6,
∴S △ABC =S △ADC +S △ABD =6+6=12.
故选C.