lim (tanx-sinx)⼀x^2*sinx x趋于0求极限怎么解

2025-01-19 17:20:10
推荐回答(1个)
回答1:

lim (tanx-sinx)/(x^2*sinx)
= limtanx (1-cosx)/(x^2*sinx) (等价无穷小代换)
= limx (x^2/2)/(x^2*x) = 1/2