D: 0 ≤ y ≤ 2, 0 ≤ x ≤ 2yI = ∫<0, 2>dy∫<0, 2y>(2x+y)dx = ∫<0, 2>dy[x^2+yx]<0, 2y>= ∫<0, 2>6y^2dy = [2y^3]<0, 2> = 16
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