y'=[1/(x+√(a^2+x^2))]*[x+√(a^2+x^2)]'
=[1/(x+√(a^2+x^2))]*[1+2x/2√(a^2+x^2)]
=[1/(x+√(a^2+x^2))]*[(√(a^2+x^2)+x)/√(a^2+x^2)]
=1/√(a^2+x^2)
y'={1/[x+√(a²+x²)]}*[x+√(a²+x²)]'
={1/[x+√(a²+x²)]}*[1+1/2√(a²+x²)*(a²+x²)']
={1/[x+√(a²+x²)]}*[1+2x/2√(a²+x²)]
={1/[x+√(a²+x²)]}*[1+x/√(a²+x²)]
={1/[x+√(a²+x²)]}*{[√(a²+x²)+x]/√(a²+x²)}
=1/√(a²+x²)
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