已知3x=2y=5z≠0,求(x+2y+3z)÷(x-y+z)的值

2025-01-20 00:57:27
推荐回答(1个)
回答1:

解答:

设3x=2y=5z=k

∴x=k/3,y=k/2,z=k/5

(x+2y+3z)÷(x-y+z)

=(k/3+2k/2+3k/5)÷(k/3-k/2+k/5)

=29k/15 ÷ k/30

=58.