推荐回答(2个)
在宇宙中,只有恒星这样的大质量天体才会自发地出现引力坍缩的情况。由于恒星的质量很大,它们存在很强的引力坍缩效应,始终有挤压自身的趋势。但由于恒星内部核聚变反应能够产生很强的辐射压,这可以避免引力坍缩。当恒星死亡之后,恒星自身巨大的质量将会把自身挤压成致密的天体——白矮星、或者中子星、甚至是黑洞。
![](/picurl?url=https%3A%2F%2Fiknow-pic.cdn.bcebos.com%2F503d269759ee3d6dfe1bcbb653166d224e4adeea%3Fx-bce-process%3Dimage%252Fresize%252Cm_lfit%252Cw_600%252Ch_800%252Climit_1%252Fquality%252Cq_85%252Fformat%252Cf_auto)
对于地球这样质量很小的天体,自发情况下是不可能坍缩成篮球大小的。如果想要实现这样的效果,就必须消耗巨大的能量。根据下式可以计算出天体的引力结合能U:
![](/picurl?url=https%3A%2F%2Fiknow-pic.cdn.bcebos.com%2F3c6d55fbb2fb4316c3c2360730a4462308f7d3ea%3Fx-bce-process%3Dimage%252Fresize%252Cm_lfit%252Cw_600%252Ch_800%252Climit_1%252Fquality%252Cq_85%252Fformat%252Cf_auto)
在上式中,G表示万有引力常数,M表示天体质量,r表示天体半径。
在正常情况下,地球的质量为5.972×10^24千克,平均半径为6371千米,可以得到地球的引力结合能约为2.24×10^32焦耳。如果地球质量保持不变,被压缩为篮球大小,那么,此时地球的半径只有12.3厘米,代入上式可以得到对应的引力结合能约为1.16×10^40焦耳。为使地球在质量不变的情况下被压缩成篮球大小,将需要高达1.16×10^40焦耳的能量,这相当于太阳在96万年里所释放出的能量总和,或者相当于6500亿亿吨反物质湮灭之后所释放出的能量。因此,题主的假设基本上不可能实现。
此外,如果地球在某种超高压的环境中被压缩成篮球的大小,它的平均密度将会达到7.66×10^26千克/立方米,这要比典型中子星由于平均密度(5×10^17)高得多。但此时地球并不是黑洞,因为地球的史瓦西半径约为8.8毫米。不过,此时的地球也不再是由普通物质组成,而是成为了致密的中子星。
一个物体缩小必须加以巨大的压力,而且会释放出大量的热,而地球必须在一个密闭的容器里,而这个热又必须及时的散发出来,使地球的温度极低,这样的一个环境,这个宇宙中没有。必须到另一个宇宙中去。如果把地球压缩成篮球这么大,地球的热量足以产生巨大的爆炸,使地球爆炸成无数的碎块飞向太空深处。
一个物体缩小和扩大是物质内部的运动速度,同时伴随着温度,运动速度快证明内部的温度高,体积就大,反之体积就小。我们日常生活中水烧开后变成气体体积大,没有烧开之前水平面和烧开后的水平面高低是不一样的。为什么水会变成蒸汽,因为吸收了大量的热,如果要把这些蒸汽再变成水就必须冷却,这必须要有外因条件。那就是外部环境冷,如果外部没有这个环境,用机械的力量强压,这个物体产生的热足以使这个物体爆炸。
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