大学高数隐函数问题

2025-01-20 04:36:35
推荐回答(1个)
回答1:

两边同时微分,得
e^y*2xdx+x^2e^ydy+2ydy=0
=>(x^2e^y+2y)dy=-e^y*2xdx
=>dy/dx=(-e^y*2x)÷(x^2e^y+2y)
=>dy/dx(1,0)=(-e^0*2)÷(1^2e^0+0)=-2÷1=-2