java中switch中case选择错误重新继续选择

2025-04-03 04:11:59
推荐回答(2个)
回答1:

public static void main(String[]args){
    System.out.println("---------------------");
    System.out.println("欢迎使用本系统,请选择:");
    System.out.println("1.登录系统");
    System.out.println("2.退出");
    System.out.println("---------------------");
    Scanner input = new Scanner(System.in);
    home(input, null);
}

private static void home(Scanner input, Integer tag){
    // 若tag不为空,则表示下级菜单返回上级菜单的标识,直接进入case选项;若tag为空,则表示正常流程,需要用户输入
    tag = tag == null ? input.nextInt() : tag;  
    switch (tag){
        case 1:
            System.out.println("---------------------");
            System.out.println("请选择以下服务:");
            System.out.println("1.客户信息管理");
            System.out.println("2.购物结算");
            System.out.println("3.真情回馈");
            System.out.println("4.注销");
            System.out.println("---------------------");
            menu(input, null);
            break;
        case 2:
            System.out.println("---------------------");
            System.out.println("谢谢您的使用!");
            System.out.println("---------------------");
            break;
        default:
            System.out.println("---------------------");
            System.out.println("输入错误, 请重新选择:");
            System.out.println("---------------------");
            home(input, null);
            break;
    }
}

private static void menu(Scanner input, Integer tag){
    tag = tag == null ? input.nextInt() : tag;
    switch(tag){
        case 1:
            System.out.println("---------------------");
            System.out.println("1.显示所有客户信息");
            System.out.println("2.添加客户信息");
            System.out.println("3.修改客户信息");
            System.out.println("4.查询客户信息");
            System.out.println("返回上一级请按 *");
            System.out.println("---------------------");
            back(input, 1);
            break;
        case 2:
            System.out.println("---------------------");
            System.out.println("暂无服务");
            System.out.println("---------------------");
            break;
        case 3:
            System.out.println("---------------------");
            System.out.println("1.幸运大放送");
            System.out.println("2.幸运抽奖");
            System.out.println("3.生日问候");
            System.out.println("返回上一级请按 *");
            System.out.println("---------------------");
            back(input, 3);
            break;
        case 4:
            System.out.println("---------------------");
            System.out.println("注销成功!");
            System.out.println("---------------------");
            break;
        default:
            System.out.println("---------------------");
            System.out.println("输入错误, 请重新选择:");
            System.out.println("---------------------");
            menu(input, null);
            break;
    }
}

private static void back(Scanner input, Integer tag){
    String c = input.next();
    switch(c){
        case "*":
            home(input, 1);
            break;
        default:
            System.out.println("---------------------");
            System.out.println("输入错误, 请重新选择:");
            System.out.println("---------------------");
            menu(input, tag);
            break;
    }
}

回答2:

import java.util.Scanner;
public class xuanze {

public static void main(String[]args){
xitong();
}
public static void xitong(){
System.out.println("\t欢迎使用本系统\t");
System.out.println("\t1.登录系统\t");
System.out.println("\t2.退出\t");
Scanner input=new Scanner(System.in);
System.out.println("请选择,输入数字:");
int a=input.nextInt();
switch (a){
case 1:
System.out.println("1.客户信息管理");
System.out.println("2.购物结算");
System.out.println("3.真情回馈");
System.out.println("4.注销");
System.out.println("请继续输入数字选择:");
int b=input.nextInt();
switch(b){
case 1:
System.out.println("1.显示所有客户信息");
System.out.println("2.添加客户信息");
System.out.println("3.修改客户信息");
System.out.println("4.查询客户信息");
break;
case 2:
System.out.println("暂无服务");
break;
case 3:
System.out.println("1.幸运大放送");
System.out.println("2.幸运抽奖");
System.out.println("3.生日问候");
break;
default:
System.out.println("暂无服务");
}
break;
case 2:
System.out.println("谢谢您的使用!");
break;
default:
System.out.println("输入错误,请重新输入");
xitong();
}
}
}
//这样可以实现你要的功能,用的是迭代,每次输入错误后会再重新执行这个函数

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