鸡兔同笼,共有262只脚,兔比鸡少20只鸡和兔各有多少只 四年级题

2025-02-12 15:12:07
推荐回答(4个)
回答1:

鸡有178只,兔有84只。

解:设鸡有x只,兔子有(262-x)只。

由题意得:2x-4*(262-x)=20

解得:x=178

兔的数量 262-x=84

答:鸡有178只,兔子有84只。

扩展资料

“鸡兔同笼问题”是我国古算书《孙子算经》中的数学问题:“今有雉(鸡)兔同笼,上有三十五头,下有九十四足。问雉兔各几何。”

 译文:有若干只鸡和兔在同个笼子里,从上面数,有三十五个头;从下面数,有九十四只脚。笼中各有几只鸡和兔?

解题思路:用一元一次方程解决。

解法:设鸡有x只,兔有(35-X)只

由题意得:

解得:x=23

兔的数量 35-x=12

答:鸡有23只,兔有12只。

参考资料来源:百度百科—一元一次方程

回答2:

鸡有57只,兔子有37只。
每只鸡有2只脚,每只兔子有4只脚。
那么一只兔子的脚的数量就是一只鸡脚的数量的2倍。
兔子比鸡少20只,因此兔子的脚的数量就比鸡脚的数量少20乘以4=80只。
鸡脚的总数量:
(262+80)除以6
=342除以6
=57(只)
兔子的数量:
57-20
=37(只)
注意:
在计算的时候,要注意兔子是四条腿,鸡是2条腿。

回答3:

鸡比兔多20只,40只脚。262-40=222(只),因为剩余鸡、兔数量相同共222只脚。剩余鸡数=兔数=222/(4+2)=37(只),所以鸡共37+20=57(只),兔37只。

回答4:

解:设鸡是x,兔子是(x-20)
2x+4(x-20)=262
6x=262+80
6x=342
x=342÷6
x=62
x-20=62-20=42
答:

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