(1)
a3=9=a1+2d
a2²=a1a7
(9-d)²=(9-2d)(9+4d)
81+d²-18d=81-18d+36d-8d²
9d²-36d=0
d=4,a1=1
an=1+4(n-1)=4n-3
(2)
bn=1+4(4n-3-1)=16n-15
bn+1=16(n+1)-15=16n+1
bn+1-bn=16
故bn为首相为1,公差为16的等比数列
1/17+1/((16×2-15)(16×3-15)
1/(16×2-15)-1/(16×3-15)=16×1/((16×2-15)(16×3-15)
所以S 1/(bnbn+1)=
1/16×[ (1/(16×1-15)-1/(16×2-15))+1/(16×2-15)-1/(16×3-15))+....+1/(16×n-15)-1/(16×(n+1)-15))]
Sn=1/16×[1/(16×1-15)-1/(16×(n+1)-15))
Sn=1/16(1-1/(bn+1))
Sn=1/16-1/(256n+16)
第二问bn=?那个下标看不清。