推荐回答（2个）
试配强度=40+1.645*5=48.2
水胶比=0.53*42.5*0.85/48.2+0.53*0.20*0.85*42.5=19.1/52=0.37
查表用水量为225， 225×（1-18%）≈ 185
水泥用量=185/0.37=500
粉煤灰=500*13%*1.4=65*1.3≈ 85
膨胀剂=500*8%=40
减水剂=500*1.4%=7
掺粉煤灰后水泥用量500-85=415
砂石用量=2410-415-185-85-40-7=1678
经验取砂率41%
砂=1678*41%=688
石=1678-688=990
配合比即：
水泥415
水185
砂688
石子990
粉煤灰85
膨胀剂40
减水剂7
415+185+688+990+85+40+7=2410
①如实测值为2460kg/m3
2410/2460=0.98
水泥415*0.98=407
水185*0.98=181
砂688*0.98= 655
石子990*0.98=970
粉煤灰85*0.98=83
膨胀剂40*0.98=39
减水剂7*0.98=6.98
②如砂含水率为7％，请对①配合比进行调整（石子含水率为0）
用水量181-181*7％=168
用砂量655+13=668
因此
水泥407
水183
砂668
石子990
粉煤灰85
膨胀剂40
减水剂7
这只是理论配合比，要得到精确配合比需做大量工作，体积比要比质量比要准确，搅拌后混凝土工作性不好，利用外加剂尽量降低用水量，以控制水灰比砂粗增大砂率泌水增加细砂泌浆增加胶凝材料.
（包括上下调整水胶比，共三个配合比)
只是在设计取出的水胶比0.37的基础上加减0.05，即0.42 ，0.37 ，0.32三个水胶比之间根据胶水比曲线图对应的强度，以调整更准确的配合比。
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