在函数maxmin(.......)中输入一组数,求其中的最大最小值。在主函数中输出最大最小值。

2024-12-02 16:57:43
推荐回答(2个)
回答1:

算法如下:

#include

int max(int a[]);

int min(int a[]);

void main()

{

int a[10],i;

for(i=0;i<10;i++)

{

printf("请输入第%d个数:\n",i+1);

scanf("%d",&a[i]);

}

printf("最大值是:%d\n",max(a));

printf("最小值是:%d\n",min(a));

}

int max(int a[])

{

int j,s1;

s1=a[0];

for(j=1;j<10;j++)

)

if(a[j]

s2=a[j];

}

return s2;

end

扩展资料:

maxmin的其他领域的应用:

MaxMin1D是NI Labwindows CVI开发环境中的一个系统函数,通过该函数可以获取一维数组的最大值、最小值以及最大值和最小值在数组中的序号。

max-min准则:

又称最大-最小准则、小中取大准则或悲观准则,为不确定型决策的决策准则之一,这种方法的基本态度是悲观与保守。

表明决策者应在各个方案中选择最坏的可能结果,然后择取提供最坏可能结果中的最佳者。具体做法是,找出每个方案的最坏可能结果即最小值,然后选出其最坏结果中能提供最大报酬,即最大值的那个方案。它指导人们去使最小可能结果最大化。

参考资料来源:百度百科-max-min准则

参考资料来源:百度百科-MaxMin1D函数

回答2:

代码: #include
int max(int a[]);
int min(int a[]);void main()
{
int a[10],i;
for(i=0;i<10;i++)
{
printf("请输入第%d个数:\n",i+1);
scanf("%d",&a[i]);
}
printf("最大值是:%d\n",max(a));
printf("最小值是:%d\n",min(a));
}int max(int a[])
{
int j,s1;
s1=a[0];
for(j=1;j<10;j++)
{
if(a[j]>s1)
s1=a[j];
}
return s1;
}int min(int a[])
{
int j,s2;
s2=a[0];
for(j=1;j<10;j++)
{
if(a[j] s2=a[j];
}
return s2;
}
图:

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