若X-Y=√2-1,XY=√2,则代数式(X-1)(Y+1)的值等于多少

2025-03-30 12:18:58
推荐回答(1个)
回答1:

(X-1)(Y+1)
=xy+x-y-1
=xy+(x-y)-1
=√2+√2-1+1
=2√2