直流电机失磁飞车的问题

2025-04-03 01:35:29
推荐回答(2个)
回答1:

飞车就是指转速突然升高,在正常情况下,电枢绕组和励磁绕组中的电流是不变的,励磁绕组产生的磁场驱动电枢内的电流,当励磁绕组突然消失,我们就可以认为,励磁绕组产生的磁场强度就是磁通突然减小甚至消失,那么在减小至消失的过程中,根据直流电动机的转速公式我们大概可以知道:转速=(U-IaRa)/(CeΦ),被除数是磁通,那么磁通越小,电机转速越高,当磁通为0时,没有意义,那么电机转速为0。
实际上,转速n不可能为无穷大。 只是一个很高的,危险的转速,即:飞车。 当磁场减弱时,因转速与磁场成反比,但随转速的增加各种阻力也将剧增,转矩下降,直到转速出现最高值(飞车)。如果磁场再继续减弱,随着转矩的减小电机的转速又将下降,直到停止。 由于转速下降,反电势减小,电枢电流剧增。 所以, 直流电机失磁,轻载时飞车。重载时烧电枢。

回答2:

公式是对的,说失磁后,转速上升,是说在空载的情况下,而在带有重负载的情况下,就如你所说,励磁没有了,反电动势E减小或是失去,电枢电流上升,Ia=U-E/Ra,同时转矩减小,不满足负载的要求,电机减速停车,此时电枢电流急剧升高,直至烧毁电枢绕组和换向器,而轻载时,负荷太轻,失磁后,还有剩磁的存在,此时电枢电流急剧上升,电磁转矩T大大于空载转矩,造成飞车

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