一道数学应用题

2024-11-08 03:07:16
推荐回答(5个)
回答1:

两天内售完,所以
第一天卖掉1000×60%=600千克,
当天剩下1000×﹙1-60%﹚=400千克新鲜水果

因为水果会失去水分,所以第二天由于失去水分,失去400×﹙98%-97.5%﹚=2千克 水分

也就是400-2=398千克
所以实际卖掉的水果是600+398=998千克
要使利润维持在20%,而且是每斤一元的价格购进了1000斤新鲜水果

说以营业额应该是1000*1*(1+20%)=1200元
所以定价为1200÷998=1.202元

回答2:

设平均售价为x元/斤。 首先求出总重量降低的百分数:设原来水果的总重量为100,含水为98,果为2,最后果占2.5%=2/80,说明最后水果重量为80,故总重量为原来的80%(本题一定要以不变的果作为等量关系来分析)。 所以得到60040080%1200,1.30.xxx 【注意】: 以下解法为错解: 设平均售价为x元/斤,则成本为1000元, 600400198%97.5%1200,1.20.xxx

回答3:

1000斤水果,第一天能卖60%,也就是600斤,第二天这400斤就变成了398斤了,因为含水量变了,所以重量减少了98% - 97.5% = 0.5%。这1000斤的成本是1000元,利润要20%的话,全部卖完得收回1200元,于是定价=1200元/(600斤+398斤)= 1200/998 = 1.202,只要定价大于1.202就都行

回答4:

解:1000×﹙1-60%﹚=400千克
400×﹙1-98%﹚=8千克
8÷﹙1-97.5﹚=320千克
1000×60%=600千克
1×1000×﹙1+20﹚=1200元
1200÷﹙600+320﹚≈1.30元。

回答5:

解:1000×﹙1-60%﹚=400千克
400×﹙1-98%﹚=8千克
8÷﹙1-97.5﹚=320千克
1000×60%=600千克
1×1000×﹙1+20﹚=1200元
1200÷﹙600+320﹚≈1.30元

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