用配方法解一元二次方程2x눀+1=3x

2024-12-01 08:44:59
推荐回答(5个)
回答1:

2x²-3x=-1
x²-3/2x=-1/2
x²-3/2x+(3/4)²=-1/2+(3/4)²
(x-3/4)²=1/16
x-3/4=±1/4
x1=1 x2=1/2

回答2:

2x²-3x+1=0
2(x²-3x/2+1/2)=0
(x²-3x/2+9/16)=1/16
(x-3/4)²=(1/4)²
x-3/4=±(1/4)
x=3/4±(1/4)
x=1,x=1/2

回答3:

2x²+1=3x

2x²-3x=-1
x²-3x/2=-1/2
x²-3x/2+9/16=-1/2+9/16(加上3/2一半的²)
(x-3/4)²=1/16
x-3/4=±1/4
x-3/4=1/4,x-3/4=-1/4

x=1, x=1/2

回答4:

x^2-3x/2+1/2=0
(x-3/4)^2=9/16-1/2=1/16
x-3/4=1/4或-1/4
x1=1,x2=1/2

回答5: