∫[(2x-3)/(x²-2x+2)]dx=∫(2x-2)/(x²-2x+2) dx-∫1/(x²-2x+2) dx=∫d(x²-2x+2)/(x²-2x+2) dx-∫d(x-1)/[(x-1)²+1] =ln(x²-2x+2)-arctan(x-1)+C
