高中数学,参数方程,要详解!急!

2025-03-22 22:02:35
推荐回答(2个)
回答1:


回答2:

1,C;y^2=2x
l;x-y-3=0
2,联立直线曲线
t^2-4t-3=0
M(x1,y1),N(x2,y2)
x1+x2=4,x1x2=-3
lPMl^2+lPNl^2=(x1+x2)^2-2x1x2=22
lPMl+lPNl=√(x1+x2)^2-4x1x2=2√7
lPMl*lPNl=-x1x2=3
lMNl=lPMl+lPNl=2√7
1/lPMl+1/lPNl=lPMl+lPNl/lPMl*lPNl=2√7/3