求∫2xcos2xdx 高手指点啊

2024-12-03 02:11:05
推荐回答(1个)
回答1:

∫ 2xcos2x dx
= ∫ xcos2x d(2x)
= ∫ x d(sin2x)
= xsin2x - ∫ sin2x dx
= xsin2x - (1/2)∫ sin2x d(2x)
= xsin2x - (1/2)(- cos2x) + C
= xsin2x + (1/2)cos2x + C