求高手将此通达信{风险测评} 指标转成博易大师可以用指标 谢谢!分二部分发

2025-02-13 03:21:22
推荐回答(2个)
回答1:

在博易大师上仿一个,不见得好, 

原码太长,

回答2:

{风险测评-第一部分}
RSVA1:=(CLOSE-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
RSVA2:=100*(HHV(HIGH,9)-CLOSE)/(HHV(HIGH,9)-LLV(LOW,9));
VAR21:=SMA(RSVA2,9,1)+100;
VAR11:=SMA(RSVA1,3,1);
VAR51:=SMA(VAR11,3,1)+100;
顶底线:=VAR51-VAR21+50;
VAR2:=LLV(LOW,33);
VAR3:=HHV(HIGH,21);
VAR4:=EMA((CLOSE-VAR2)/(VAR3-VAR2)*100,10)*(-1)+100;
趋势:=100-EMA(0.191*REF(VAR4,1)+0.809*VAR4,1);
STICKLINE(C,100,90,2,0),COLORFFCC33;
STICKLINE(C,90,80,2,0),COLORFF9933;
STICKLINE(顶底线>REF(顶底线,1),20,80,2,0),COLOR9999FF;
STICKLINE(顶底线STICKLINE((趋势>REF(趋势,1) AND 顶底线STICKLINE((趋势REF(顶底线,1)),20,80,2,0),COLOR009966;
STICKLINE(C,20,10,2,0),COLORFF6633;
STICKLINE(C,10,0,2,0),COLORFF3333;
底线:10,COLORWHITE;
顶线:90,COLORWHITE;
趋势线:100-EMA(0.191*REF(VAR4,1)+0.809*VAR4,1),LINETHICK2,COLORBLUE;
当前安全度:100-EMA(0.191*REF(VAR4,1)+0.809*VAR4,1),CIRCLEDOT,LINETHICK2,COLORRED;
{DRAWTEXT(CURRBARSCOUNT=6,5,'高安全区'),COLORWHITE;
DRAWTEXT(CURRBARSCOUNT=6,15,'安全区'),COLORWHITE;
DRAWTEXT(CURRBARSCOUNT=6,45,'绿区持币'),COLORFFC000;
DRAWTEXT(CURRBARSCOUNT=6,50,'(投资区)'),COLORWHITE;
DRAWTEXT(CURRBARSCOUNT=6,55,'粉区持股'),COLORFFC000;
DRAWTEXT(CURRBARSCOUNT=6,85,'风险区'),COLORWHITE;
DRAWTEXT(CURRBARSCOUNT=6,95,'高风险区'),COLORWHITE;}

{强拉升}
Y1:=LLV(L,17);
Y2:=SMA(ABS(L-REF(L,1)),17,1);
Y3:=SMA(MAX(L-REF(L,1),0),17,2);
Q:=-(EMA(IF(L<=Y1,Y2/Y3,-3),1));
STICKLINE(CROSS(Q,0),15,0,2,0),COLORYELLOW;
强拉升:IF(CROSS(Q,0),1,0),COLORYELLOW;
Q1:=(CLOSE-MA(CLOSE,40))/MA(CLOSE,40)*100,COLOR00FF00,LINETHICK2;
STICKLINE(CROSS(Q1,-24),20,0,2,0),COLORMAGENTA;
加强拉升: IF(CROSS(Q1,-24),1,0),COLORMAGENTA;
VAR22:=EMA(EMA(EMA((2*CLOSE+HIGH+LOW)/4,4),4),4);
天:=(MA((VAR22-REF(VAR22,1))/REF(VAR22,1)*100,2));
地:=(MA((VAR22-REF(VAR22,1))/REF(VAR22,1)*100,1));
STICKLINE(地>天 AND 地<0,10,0,1,0),COLORRED;
STICKLINE(地>天 AND 地<0,10,0,1,0),COLORRED;
开始拉升:IF(地>天 AND 地<0,1,0);
{上面是两部分,已测试通过,替换了一函数可能跟原公式有点误差,你可在通达信中做一下对照}

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