高中必修一化学的气体摩尔质量的3个公式分别是神马意思?

2025-04-04 02:30:26
推荐回答(2个)
回答1:

(1)n=m/m,n是物质的量(mol),m是质量(g),m是摩尔质量(g/mol)
(2)n=n/na,n是微粒数,na是阿附加德罗常数
(3)n=v/vm,v是气体的体积(l),vm是一定条件下的气体摩尔体积(l/mol),在标准状况下,vm=22.4l/mol
(4)n=cv,c是溶液中溶质的物质的量浓度(mol/l),v是溶液的体积(l)2、知道和熟练常见的转换及推论的公式
(1)物质的量浓度(c)与质量分数(w)之间的转换
c=1000dw/m,d是溶液的密度(g/cm3),m是溶质的摩尔质量(g/mol)
(2)饱和溶液的质量分数(w)与溶解度(s)之间的转换
w=s/(100+s)
(3)相同状况下,气体的体积之比=物质的量之比=气体的分子数之比
v(a):v(b)=n(a):n(b)=n(a):n(b)
(4)相同状况下,气体的密度之比=摩尔质量之比=相对分子质量之比
d(a):d(b)=m(a):m(b)=mr(a):mr(b)
所以,若说某气体对氢气的相对密度为16,即该气体的mr=16×2=32

回答2:

Vm=V/n
就是说一定体积的气体与所含粒子的物质的量的比值是一个常数,当条件为标准状况时,Vm=22.4L/mol
n=V/Vm条件一定时,气体的物质的量与体成正比
V=n*Vm条件一定时,气体体积与物质的量成正比
注意:只有在标准状况下,Vm才等于22.4

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