(1+1/2)×(1+1/3)×(1+1/4)×.....×(1+1/100)=3/2×4/3×5/4×6/5×......×100/99×101/100接着中间的项都消掉=1/2×101=101/2
通分之后得:(3/2)x (4/3)x (5/4)x …… x (101/100)中间的分子分母相互取消了,剩下101/2=50.5
原式=(3/2)*(4/3)*(5/4)………………*(101/100)=101/2
3/2*4/3……*101/100=55.5