求1——300的自然数中,含有数字2的共有多少个?数字2一共出现了多少次?
推荐回答(5个)
含有2的共有138个,数字2一共出现160次
1-100除了20-29,每10个数中有一个。共有9+10=19个
101-200除了120-129和200,每10个数中有一个。共有9+10+1=20个
201-300共有99个
1-300中共有19+20+99=138个
不考虑百位,1-99中除了20-29,每10个数出现一次2;20-29十位出现10次,个位出现1次。总次数=9++10+1=20次
1-300不考虑2**中的百位,共出现=20*3=60次。2**中百位共出现100次。
总次数=60+100=160次
含2 出现次数
0-99 19 20
100-199 19 20
200-300 119 120
合计 157 160
个位上是2的、、2~292 30个
十位上是2的、、20~29 120~129 220~229 30个
百位上是2的、、200~299 100个
正好二个2的、、22、122、220~229,202~292(除222) 21个
正好3个2的、、 222 1个
所以30+30+100-21-1=138
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全部2 = 160
有2的数 = 138
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