15问答网 > 函数y=cosx·sin(x+二分之派）的最小正周期是多少？

函数y=cosx·sin(x+二分之派）的最小正周期是多少？

2025-04-04 09:43:49
推荐回答（3个）
回答1：

y=-(cosx)^2=-(cos2x+1)/2
最小正周期为pi

回答2：

解：由题意可得：
sin(x+π/2)=cosx
所以y=cosx*sin(x+π/2)=(cosx)^2=(cos2x+1)/2
所以T(min)=2π/2=π

回答3：

π

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