如何用C语言写出一个九九乘法表,输出格式是倒三角形状,就是上面多下面少?

2025-01-04 09:46:38
推荐回答(5个)
回答1:

#include
void main()
{
int i;
int j;

for (i = 1; i <= 9; i++)
{
for (j = 1; j <= i; j++)
{
printf("%-4d*%-4d=%-4d\n", j, i, j * i);
}
}
}
就这样吧,上三角的没见过,可以考虑换行,如果需要,再联系。

回答2:

这些布局问题,试几次就知道了
#include

void main()
{
int i, j;
for (i = 1; i != 10; ++i)
{
for (j = 9; j >= i; --j)
{
printf("%d*%d=%d\t", j, i, i * j);
}
printf("\n");
}
}

回答3:

#include "stdio.h"
main()
{ int i,j;
printf("**********************************************\n");
printf("9*9乘法口诀表\n");
printf("**********************************************\n");
for(i=9;i>=1;i--)
{
for(j=1;j<=i;j++)
printf("%d*%d=%d;",j,i,i*j);
printf("\n");
}
}

回答4:

int i,j;
for(i=1;i<10;i++)
{
for(j=9;j>=i;j--)
printf("%d*%d=%-3d",i,j,i*j);
puts("");
}

回答5:

#include
void main()
{
int i,j;
for(i=1;i<=j;i++)
{
for(j=9;j>=1;j--)
printf("%d*%d=%d",j,i,j*i);
printf("\n");
}
printf("\n");
}
就这样完整的过程

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