请问在C语言中#if (0) define .. ; 请问这个宏定义会定义么?例如例子: #if (0) define gets(n)

((n)*(n));如果我在函数中调用gets会报错么?会出现理想效果不?
2025-04-08 07:54:30
推荐回答(2个)
回答1:

没有说得那么繁琐.
因为对于一个大程序而言,我们可能要定义很多常量( 不管是放在源文件还是头文件 ),那么我们有时考虑定义某个常量时,我们就必须返回检查原来此常量是否定义,但这样做很麻烦.if defined宏正是为这种情况提供了解决方案.举个例子,如下:

#define ....
#define ....
........
........
#define a 100
.......
此时,我们要检查a是否定义(假设我们已经记不着这点了),或者我们要给a一个不同的值,就加入如下句子
#if defined a
#undef a
#define a 200
#endif
上述语句检验a是否被定义,如果被定义,则用#undef语句解除定义,并重新定义a为200

同样,检验a是否定义:
#ifndef a //如果a没有被定义
#define a 100
#endif

以上所用的宏中:#undef为解除定义,#ifndef是if not defined的缩写,即如果没有定义。

这就是#if defined 的唯一作用!

回答2:

应该是这样的
#if (0)
#define gets(n) ((n)*(n))
#endif
这时这个gets(n)的宏并不会被定义.这样做的目的估计是为了调试方便,比如把if(0)改成if(1),这个宏就被定义了.

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