①热敏电阻的电流与电压从零开始变化,则滑动变阻器应采用分压接法,
由图示电路图可知,实验应采用图b所示电路.
②通过定值电阻R1的电流I1=
=U R1
=0.036A,通过热敏电阻的电流I2=I-I1=0.070A-0.036A=0.034A,9V 250Ω
由图a所示图象可知,0.034A=34mA所对应的电压U热=5.2V,电阻R2两端电压U2=U-U热=9V-5.2V=3.8V,
电阻R2的阻值R2=
=U2 I2
≈111.8Ω.3.8V 0.034A
故答案为:①b;②5.2;111.8.