15问答网 > （40-x)(20+x)=1200解方程

（40-x)(20+x)=1200解方程

2025-04-06 18:21:40
推荐回答（4个）
回答1：

(x-40)(x+20)=-1200
x^2-20x-800=-1200
x^2-20x+400=0
因为△=（-20）^2-4*400=-3*400<0
所以原方程无实数根。

回答2：

原式→800+20X-X^2=1200→400-20X+X^2=0 △=(-20)^2-4*400=-1200…方程无解…

回答3：

-(x-40)(x+40)=1200; -(x'2-1600)=1200;x'2+1600=-1200;x'2=400;x=+-20

回答4：

原方程无实数根

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