用代数法解下列方程组!!!!!! 4(x-y-1)=3(1-y)-2 x⼀2+y⼀3=2

如题 1!!!!!!!!!!!!!!!!!!!!!!
2024-12-05 05:18:12
推荐回答(1个)
回答1:

x/2+y/3=2 ,则x=4-2y/3,代入 4(x-y-1)=3(1-y)-2,得
4(4-2y/3-y-1)=3(1-y)-2
则12-20y/3=1-3y
则11=11y/3
解得y=3
代入x=4-2y/3,解得x=2