6年级下册数学书第36页的第1,2,3,4题怎么做?
推荐回答(5个)
1、一项工程 甲乙合做6天完成,乙独做10天完成,甲独做要几天完成?
解:
甲的工作效率=1/6-1/10=1/15
甲独做需要1/(1/15)=15天完成
2、一项工作,甲5小时先完成4分之1,乙6小时又完成剩下任务的一半,最后余下的工作有甲乙合作,还需要多长时间能完成?
解:甲的工作效率=(1/4)/5=1/20
乙完成(1-1/4)×1/2=3/8
乙的工作效率=(3/8)/6=1/16
甲乙的工作效率和=1/20+1/16=9/80
此时还有1-1/4-3/8=3/8没有完成
还需要(3/8)/(9/80)=10/3小时
3、工程队30天完成一项工程,先由18人做,12天完成了工程的3/1,如果按时完成还要增加多少人?
解:每个人的工作效率=(1/3)/(12×18)=1/648
按时完成,还需要做30-12=18天
按时完成需要的人员(1-1/3)/(1/648×18)=24人
需要增加24-18=6人
4、甲乙两人加工一批零件,甲先加工1.5小时,乙再加工,完成任务时,甲完成这批零件的八分之五.已知甲乙的共效比是3:2.问:甲单独加工完成着批零件需多少小时?
解:甲乙工效比=3:2
也就是工作量之比=3:2
乙完成的是甲的2/3
乙完成(1-5/8)=3/8
那么甲和乙一起工作时,完成的工作量=(3/8)/(2/3)=9/16
所以甲单独完成需要1.5/(5/8-9/16)=1.5/(1/16)=24小时
一、1、1:24和1.4:1.6
12:14=12/14=6/7
1.4:1.6=14/16=7/8
不能住成比例
2、2:8和30:120
2:8=2/8=1/4
30:120=30/120=1/4
2:8=30:120
3、3:3和30:40
2:3=2/5
30:40=30/40=3/4
不能住成比例
4、5:10和100:200
5:10=5/10=1/2
100:200=100/200=1/2
5:10=100:200
二、
4:2=4/12=1/3
5:15=5/15=1/3
4:12=5:15
1/2:1/4=1/2×4=2
1/3:1/6=1/3×6=2
1/2:1/4=1/3:1/6
三、
10:2=10/2=5
15:3=15/3=5
10:2=15:3
20:4=20/4=5
25:5=25/5=5
20:4=25:5
四、
3:4=3/4
12:16=12/16=3/4
3 : 4= 12 : 16
外项 内项 内项 外项
如有抄袭者,绝对找骂。
一、(1)不能。(2)能 30:2=120:8 (3 )不能 (4)能 100:5=200:10 二、(1)能。 4:5=12:15 4:12=5:15 15:5=12:4 15:12=5:4 5:15=4:12 5:4=15:12 12:15=4:5 12:4=:15:5 (2) 不能。 (3)不能 (4)2/1:3/1=4/1:6/1 2/1:4/1 =3/1:6/1 6/1:3/1=4/1:2/1 6/1:4/1=3/1:2/1 3/1:2/1=6/1:4/1 3/1:6/1=2/1:4/1 4/1:6/1=2/1:3/1 4/1:2/1=6/1:3/1 三,5:1 10:2 5:1=10:2 四。 (1)可以组成。12:16=3:4 (2)在12:16=3:4中,比例的内项是16和3,外项是12和4
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