我的钱买三个铃铛还剩一元钱,买四个,还差三元钱,我有多少钱?每个铃铛多少钱?求解

2025-03-16 14:13:38
推荐回答(5个)
回答1:

每个铃铛4元。

设每个铃铛X元,共有Y元,

根据题意,买三个剩一元钱,

列式可得,Y=3X+1,

买四个还差3元钱,

列式可得,Y=4X-3,

那么Y是相等的,即3X+1=4X-3,

解方程式可得,X=4,那么Y=13,

即每个铃铛4元,手里共有13元。

扩展资料:

解一元一次方程有五步,即去分母、去括号、移项、合并同类项、系数化为1,所有步骤都根据整式和等式的性质进行。

以解方程

 

为例:

去分母,得:

去括号,得:

移项,得:

合并同类项,得:(常简写为“合并,得:”)

系数化为1,得:

在一元一次方程中,去分母一步通常乘以各分母的最小公倍数,如果分母为分数,则可化为该一项的其他部分乘以分母上分数的倒数的形式。

以方程

 

为例:

消除分母上的分数,可化简为:

进而得出方程的解。

如果分母上有无理数,则需要先将分母有理化。

参考资料来源:百度百科—一元一次方程

回答2:

每个铃铛的价格:
(4-1)-(-1)=4(元)

我有多少钱:
3X4+1=13(元)

回答3:

(3+1)÷(4-3)=4元每个

回答4:

这种类型题被人形象地称为“盈亏问题”,解决问题的关键是采取假设法,假设在某种情况下不是赢亏,而是正好。比如上面的问题,明明是买3个剩1元,我们就可以假设总钱数少一元,则问题变成买3个正好,买4个差4元。显然,每个铃铛(3+1)÷(4-3)=4元。钱数是4x3+1=13元。

回答5:

铃:1+3=4元
带:4X3+1=13元

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