一个大于1的数去除235,322,360时,余数分别为a+1,a+3,a+7,则此数是

2025-04-04 03:43:55
推荐回答(2个)
回答1:

则此数是17。
设这个数为x,则有(a,b,k,m,n均为整数):
235-(a+1)=kx (1)
322-(a+3)=mx(2)
360-(a+7)=nx (3)
(2)-(1)得:
85=5x17=(m-k)x(4)
(3)-(2)得:
34=2x17=(n-m)x(5)
由(4)和(5)得
x=17
所以m-k=5,n-m=2
得a=13,k=13,m=18,n=20

回答2:

设这个是为p,
那么
235÷p=?……a+1
322÷p=?……a+3
360÷p=?……a+7
(此时可知,a+1≥1,于是a≥0,再有p>a+7,于是p≥7)

将上面三个式子变形,
234÷p=?……a
319÷p=?……a
353÷p=?……a

于是
(319-234)÷p没有余数,(353-319)÷p也没有余数,
化简:
85÷p没有余数,34÷p也没有余数,
也就是说,
p是85与34的公因数,
而85=17×5,34=17×2
因而85与34的最大公因数为17,
那么它们的公因数为1和17,
而这个除数p≥7,
那么p=17。

因而,答案=17

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